sql 语句练习

发布时间:2014-10-23 23:29:56
来源:分享查询网

Student(S#,Sname,Sage,Ssex) 学生表 Course(C#,Cname,T#) 课程表 SC(S#,C#,score) 成绩表 Teacher(T#,Tname) 教师表 问题: 1、查询“001”课程比“002”课程成绩高的所有学生的学号; select a.S# from (select s#,score from SC where C#=’001′) a, (select s#,score from SC where C#=’002′) b where a.score>b.score and a.s#=b.s#; 2、查询平均成绩大于60分的同学的学号和平均成绩; select S#,avg(score) from sc group by S# having avg(score) >60; 3、查询所有同学的学号、姓名、选课数、总成绩; select Student.S#,Student.Sname,count(SC.C#),sum(score) from Student left Outer join SC on Student.S#=SC.S# group by Student.S#,Sname 4、查询姓“李”的老师的个数; select count(distinct(Tname)) from Teacher where Tname like ‘李%’; 5、查询没学过“叶平”老师课的同学的学号、姓名; select Student.S#,Student.Sname from Student where S# not in (select distinct( SC.S#) from SC,Course,Teacher where SC.C#=Course.C# and Teacher.T#=Course.T# and Teacher.Tname=’叶平’); 6、查询学过“001”并且也学过编号“002”课程的同学的学号、姓名; select Student.S#,Student.Sname from Student,SC where Student.S#=SC.S# and SC.C#=’001′and exists( Select * from SC as SC_2 where SC_2.S#=SC.S# and SC_2.C#=’002′); 7、查询学过“叶平”老师所教的所有课的同学的学号、姓名; select S#,Sname from Student where S# in (select S# from SC ,Course ,Teacher where SC.C#=Course.C# and Teacher.T#=Course.T# and Teacher.Tname=’叶平’ group by S# having count(SC.C#)=(select count(C#) from Course,Teacher where Teacher.T#=Course.T# and Tname=’叶平’)); 8、查询所有课程成绩小于60分的同学的学号、姓名; select S#,Sname from Student where S# not in (select Student.S# from Student,SC where S.S#=SC.S# and score>60); 9、查询没有学全所有课的同学的学号、姓名; select Student.S#,Student.Sname from Student,SC where Student.S#=SC.S# group by Student.S#,Student.Sname having count(C#) <(select count(C#) from Course); 10、查询至少有一门课与学号为“1001”的同学所学相同的同学的学号和姓名; select S#,Sname from Student,SC where Student.S#=SC.S# and C# in (select C# from SC where S#='1001'); 11、删除学习“叶平”老师课的SC表记录; Delect SC from course ,Teacher where Course.C#=SC.C# and Course.T#= Teacher.T# and Tname='叶平'; 12、查询各科成绩最高和最低的分:以如下形式显示:课程ID,最高分,最低分 SELECT L.C# 课程ID,L.score 最高分,R.score 最低分 FROM SC L ,SC R WHERE L.C# = R.C# and L.score = (SELECT MAX(IL.score) FROM SC IL,Student IM WHERE IL.C# = L.C# and IM.S#=IL.S# GROUP BY IL.C#) and R.Score = (SELECT MIN(IR.score) FROM SC IR WHERE IR.C# = R.C# GROUP BY IR.C# ); 13、查询学生平均成绩及其名次 SELECT 1+(SELECT COUNT( distinct 平均成绩) FROM (SELECT S#,AVG(score) 平均成绩 FROM SC GROUP BY S# ) T1 WHERE 平均成绩 > T2.平均成绩) 名次, S# 学生学号,平均成绩 FROM (SELECT S#,AVG(score) 平均成绩 FROM SC GROUP BY S# ) T2 ORDER BY 平均成绩 desc; 14、查询各科成绩前三名的记录:(不考虑成绩并列情况) SELECT t1.S# as 学生ID,t1.C# as 课程ID,Score as 分数 FROM SC t1 WHERE score IN (SELECT TOP 3 score FROM SC WHERE t1.C#= C# ORDER BY score DESC) ORDER BY t1.C#; 15、查询每门功成绩最好的前两名 SELECT t1.S# as 学生ID,t1.C# as 课程ID,Score as 分数 FROM SC t1 WHERE score IN (SELECT TOP 2 score FROM SC WHERE t1.C#= C# ORDER BY score DESC ) ORDER BY t1.C#; 补充: 已经知道原表 year salary —————— 2000 1000 2001 2000 2002 3000 2003 4000 解: select b.year,sum(a.salary) from salary a,salary b where a.year<=b.year group by b.year order by b.year; 在面试过程中多次碰到一道SQL查询的题目,查询A(ID,Name)表中第31至40条记录,ID作为主键可能是不是连续增长的列,完整的查询语句如下: 方法一: select top 10 * from A where ID >(select max(ID) from (select top 30 ID from A order by ID ) T) order by ID 方法二: select top 10 * from A where ID not In (select top 30 ID from A order by ID) order by ID

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